How do you evaluate #sin ((7pi)/4)#?

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Nghi N. Share
Apr 9, 2016

Answer:

#- sqrt2/2#

Explanation:

Trig table and trig unit circle -->
#sin ((7pi)/4) = sin (-pi/4 + (8pi)/4) = sin (-pi/4 + 2pi) = #
#= sin (-pi/4) = - sin (pi/4) = - sqrt2/2#

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