How do you evaluate #sqrt(4\times 30+ 15)#?

1 Answer
Jun 28, 2017

See a solution process below:

Explanation:

First, we will treat the radical the same as a parenthesis and evaluate the terms within the radical first. Using the standard or of operation we will first execute the multiplication operation:

#sqrt(color(red)(4) xx color(red)(30) + 15) = sqrt(120 + 15)#

Next, execute the addition operation within the radical:

sqrt(color(red)(120) + color(red)(15)) = sqrt(135)#

We can rewrite this expression as:

#sqrt(9 * 15)#

Using this rule of radicals we can further evaluate the expression:

#sqrt(color(red)(a) * color(blue)(b)) = sqrt(color(red)(a)) * sqrt(color(blue)(b))#

#sqrt(color(red)(9) * color(blue)(15)) = sqrt(color(red)(9)) * sqrt(color(blue)(15)) = 3 * sqrt(15) = 3sqrt(15)#

If necessary: #sqrt(15) = 3.873# rounded to the nearest thousandth.

Then:

#3sqrt(15) = 3 * 3.873 = 11.619# rounded to the nearest thousandth.