How do you evaluate #sqrt(b^2-4ac)# for a=1, b=12, c=11?

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Answer 1 · 2017-06-11T03:22:47

#10#

Substitute each value and evaluate:

#sqrt((12)^2-4(1)(11))#

#sqrt(144-44)#

#sqrt100#

Take the square root

#sqrt100=10#

Answer 2 · 2017-06-11T03:28:41

#sqrt(12^2-4*1*11)=10#

Given.

#sqrt(b^2-4ac)#

Evaluate for #a=1#, #b=12#, and #c=11#.

Insert the values for #a,b,and c# into the expression.

#sqrt(12^2-4*1*11)#

Simplify.

#sqrt(144-44)#

Simplify.

#sqrt(100)#

Simplify.

#10#