How do you evaluate #sqrt(b^2-4ac)# for a=1, b=12, c=11?

2 Answers
Jun 11, 2017

Answer:

#10#

Explanation:

Substitute each value and evaluate:

#sqrt((12)^2-4(1)(11))#

#sqrt(144-44)#

#sqrt100#

Take the square root

#sqrt100=10#

Jun 11, 2017

Answer:

#sqrt(12^2-4*1*11)=10#

Explanation:

Given.

#sqrt(b^2-4ac)#

Evaluate for #a=1#, #b=12#, and #c=11#.

Insert the values for #a,b,and c# into the expression.

#sqrt(12^2-4*1*11)#

Simplify.

#sqrt(144-44)#

Simplify.

#sqrt(100)#

Simplify.

#10#