# How do you evaluate sqrt(b^2-4ac) for a=1, b=12, c=11?

Jun 11, 2017

$10$

#### Explanation:

Substitute each value and evaluate:

$\sqrt{{\left(12\right)}^{2} - 4 \left(1\right) \left(11\right)}$

$\sqrt{144 - 44}$

$\sqrt{100}$

Take the square root

$\sqrt{100} = 10$

Jun 11, 2017

$\sqrt{{12}^{2} - 4 \cdot 1 \cdot 11} = 10$

#### Explanation:

Given.

$\sqrt{{b}^{2} - 4 a c}$

Evaluate for $a = 1$, $b = 12$, and $c = 11$.

Insert the values for $a , b , \mathmr{and} c$ into the expression.

$\sqrt{{12}^{2} - 4 \cdot 1 \cdot 11}$

Simplify.

$\sqrt{144 - 44}$

Simplify.

$\sqrt{100}$

Simplify.

$10$