How do you evaluate the algebraic expression $3(x- 3)+ 4$ for x=7?

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Answer 1 · 2016-10-29T14:59:50

$16$

To evaluate this expression you need to substitute $7$ everywhere there is an $x$ to give:

$3(7 - 3) + 4$

Then doing the basic arithmetic gives:

$3(4) + 4$

$12 + 4$

$16$

How do you evaluate the algebraic expression 3(x- 3)+ 43(x- 3)+ 4 for x=7?