# How do you evaluate the definite integral of 0 to 4 for (5 / 3x +1) dx?

It is $\frac{52}{3}$
${\int}_{0}^{4} \left(\frac{5}{3} x + 1\right) \mathrm{dx} = {\int}_{0}^{4} \left(\frac{5}{3} {x}^{2} / 2 + x\right) ' \mathrm{dx} = {\left[5 {x}^{2} / 6 + x\right]}_{0}^{4} = \frac{5}{6} \cdot {4}^{2} + 4 = \frac{52}{3}$