# How do you evaluate the expression 8x + 8y + x + 6y+ 4x if x= 1, y= 2?

Sep 20, 2015

41

#### Explanation:

Well, it means, "replace x by 1 and y by 2 in the expression, and calculate."

So let's get it done with.
We have:
$8 x + 8 y + x + 6 y + 4 x$
Putting x=1 and y=2, we have:
$= \left(8 \cdot 1\right) + \left(8 \cdot 2\right) + 1 + \left(6 \cdot 2\right) + \left(4 \cdot 1\right)$
$= 8 + 16 + 1 + 12 + 4$
$= 41$