How do you evaluate the expression #log_2 (1/32)#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer Harish Chandra Rajpoot Jul 20, 2018 #-5# Explanation: #\log_2(1/32)# #=\log_2(1/2^{5})# #=\log_2(2^{-5})# #=-5\log_2(2)# #=-5\cdot 1# #=-5# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 15592 views around the world You can reuse this answer Creative Commons License