Question

How do you evaluate the expression `(y-11)/(x-2)` when x=-4 and y=5?

Answer 1

See a solution process below:

Explanation:

Substitute `color(red)(-4)` for `color(red)(x)` and `color(blue)(5)` for `color(blue)(y)`:

`(color(blue)(y) - 11)/(color(red)(x) - 2)` becomes:

`(color(blue)(5) - 11)/(color(red)(-4) - 2) => (-6)/-6 => 1`