How do you evaluate the expressions #(4x^4)/( 24x^3)# given x= 3 and y=5?

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Answer 1 · 2016-09-06T14:54:31

Plug in 3 for x.

If x=3, then plug that into the expression (was one of the x's supposed to be y?).

#(4(3)^4)/(24(3)^3)#

Evaluate the exponents first. In order of operation, exponents come before multiplication.
#3^4 = 81# and #3^3= 27#

#(4(81))/(24(27))#

#324/648 = 1/2#

Or, you could first simplify the #x^4/x^3 = x#

Then the problem becomes #(4x)/24#

Plugging in 3 for x:

#(4(3))/24 = 12/24 = 1/2#

However, is it possible you entered the problem incorrectly? We never used y= 5. Was one of the x's supposed to be y?