# How do you evaluate the function f(x) = -1/3x+7 for f(-6)?

$f \left(- 6\right) = 9$
$\text{to evaluate "f(-6)" substitute "x=-6" into } f \left(x\right)$
$\Rightarrow f \left(\textcolor{red}{- 6}\right) = - \frac{1}{\cancel{3}} ^ 1 \times - {\cancel{\textcolor{red}{6}}}^{2} + 7$
$\textcolor{w h i t e}{\Rightarrow f \left(- 6\right)} = 2 + 7 = 9$