How do you evaluate the function f(x)=2x^2-2x+9 for f(3/2)?

Jun 4, 2018

$f \left(\frac{3}{2}\right) = \frac{21}{2}$

Explanation:

$\text{to evaluate "f(3/2)" substitute "x=3/2" into } f \left(x\right)$

$f \left(\textcolor{red}{\frac{3}{2}}\right) = 2 \times {\left(\textcolor{red}{\frac{3}{2}}\right)}^{2} - 2 \times \textcolor{red}{\frac{3}{2}} + 9$

$\textcolor{w h i t e}{\times \times x} = 2 \times \frac{9}{4} - 3 + 9$

$\textcolor{w h i t e}{\times \times x} = \frac{9}{2} + 6 = \frac{9}{2} + \frac{12}{2} = \frac{21}{2}$