How do you evaluate the function #f(x)=6x^2+2x-12# for #f(-x)#?
1 Answer
Jun 17, 2018
Explanation:
#"substitute "x=-x" into "f(x)#
#f(color(red)(-x))=6(color(red)(-x))^2+2(color(red)(-x))-12#
#color(white)(xxxxx)=6x^2-2x-12#
