# How do you evaluate the indefinite integral int (x^5)dx?

The answer is $= {x}^{6} / 6 + C$
$\int {x}^{n} \mathrm{dx} = {x}^{n + 1} / \left(n + 1\right) + C \left(n \ne - 1\right)$
$\int {x}^{5} \mathrm{dx} = {x}^{6} / 6 + C$