Question

How do you evaluate the limit `2x^2-3x` as x approaches `oo`?

Answer 1

Yhe limit does not exist (it is infinite and diverges).

Explanation:

`(2x^2-3x) = x(2x-3)`

Both `x` and `(2x-3)` increase without bound as `x` increases, hence their product increases without bound and we can therefore conclude that the limit does not exist (it is infinite and diverges).