How do you evaluate the limit #(s-1)/(s^2-1)# as s approaches #1#?
1 Answer
Oct 8, 2016
Explanation:
Note that
#(s-1)/(s^2-1) = (color(red)(cancel(color(black)(s-1))))/((color(red)(cancel(color(black)(s-1))))(s+1)) = 1/(s+1)#
with exclusion
The simplified rational expression describes a function identical to the original one, except that the original is undefined at the point
Hence:
#lim_(s->1) (s-1)/(s^2-1) = lim_(s->1) 1/(s+1) = 1/2#