How do you evaluate this expression when s = 7, a = 5, m = 3, and t = 4 #(s+1)(s^2-s+1)#?

1 Answer
Aug 24, 2017

Answer:

See a solution process below:

Explanation:

For each of occurrence of #color(red)(s)# in the expression substitute #color(red)(7)#

For this problem the variables #a# and #m# and #t# are extraneous or not used and therefore not needed.

#(color(red)(s) + 1)(color(red)(s)^2 - color(red)(s) + 1)# becomes:

#(color(red)(7) + 1)(color(red)(7)^2 - color(red)(7) + 1) =>#

#8(49 - color(red)(7) + 1) =>#

#8 * 43 =>#

#344#