How do you evaluate #w=3, x=6, y=5,# and #z=9# for #13y+wx#?

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Answer 1 · 2017-01-07T22:09:44

See full explanation below:

To evaluate this you substitute as follows:

#color(red)(3)# for #w#

#color(blue)(6)# for #x#

#color(green)(5)# for #y#

Note: #z# is not used in the expression and therefore will not be substituted:

#13color(green)(y) + color(red)(w)color(blue)(x)#

Becomes:

#(13 xx color(green)(5)) + (color(red)(3) xx color(blue)(6)) ->#

#65 + 18 ->#

#83#