# How do you expand and simplify (x-6)(6x+2)-5(x-3)^2?

Jun 5, 2016

${x}^{2} - 4 x - 57$

#### Explanation:

BEDMAS (aka PEMDAS) and FOIL will be a big part of finding the solution:

$\left(x - 6\right) \left(6 x + 2\right) - 5 {\left(x - 3\right)}^{2}$

$\left(6 {x}^{2} + 2 x - 36 x - 12\right) - 5 \left(\left(x - 3\right) \left(x - 3\right)\right)$

$\left(6 {x}^{2} - 34 x - 12\right) - 5 \left({x}^{2} - 3 x - 3 x + 9\right)$

$6 {x}^{2} - 34 x - 12 - 5 \left({x}^{2} - 6 x + 9\right)$

$6 {x}^{2} - 34 x - 12 - 5 {x}^{2} + 30 x - 45$

group like terms

${x}^{2} - 4 x - 57$