How do you expand #ln(2x-1)(x+1)#?

1 Answer
Dec 17, 2016

Answer:

#ln(2x-1)+ln(x+1)#

Explanation:

Using the #color(blue)"law of logarithns"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(logx+logyhArrlogxy)color(white)(2/2)|)))#
#color(white)(xxxxxxxx)" applies to logs in any base"#

#rArrln(2x-1)(x+1)=ln(2x-1)+ln(x+1)#