Question

How do you express `csc((10pi)/3)` as a trig function of an angle in Quadrant I?

Answer 1

`-csc(pi/3)`

Explanation:

`csc((10pi)/3)`

`=-sec((10pi)/3-2pi)=-sec((4pi)/3)`

`=-sec((4pi)/3-pi)`

`=-sec(pi/3)larrpi/3" in first quadrant"`