# How do you express #sin^4theta-cos^3theta # in terms of non-exponential trigonometric functions?

##### 1 Answer

#### Explanation:

We can use the trig identities:

And

Now

I understand these identities are a bit random. If you have a good understanding of **complex numbers** and **binomial theorem** then here is a trick that can be used to obtain **any** of these types of trig identities.

It may be a bit tedious at first but with a bit of practice you'll learn in no time and when you do you'll never forget it.

The trick is to express the trig function in terms of its complex exponential and then expand that term using the binomial theorem to the appropriate power. After which you can then re-arrange the terms back into the non power trig functions like above. If we use

If you are versed in complex numbers, remember that:

From this it can be shown:

and

So it follows that:

Now applying the binomial theorem to expand this we get:

Bringing the powers into the exponents then tidying this up a little:

And now we see have the exponential forms for

The exact same method can be applied to

I hope this helped.