# How do you express the following using fractional exponents: sqrtx*sqrtt?

By exponential definition, we have that ${n}^{\frac{a}{b}} = \sqrt[b]{{n}^{a}}$
sSo, $\sqrt{x} = {x}^{\frac{1}{2}}$ and $\sqrt{t} = {t}^{\frac{1}{2}}$
Therefore, $\sqrt{x} \cdot \sqrt{t} = {x}^{\frac{1}{2}} \cdot {t}^{\frac{1}{2}}$