How do you factor #10t^2 - 19t + 6#?

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Answer 1 · 2018-03-10T08:41:05

#(5t-2)(2t-3)#

#10t^2-19t+6#

1) multiply the coeff#" "x^2# and the constant.

#color(red)(10)t^2-19t+color(red)(6)#

#10xx6=60#

2) find the factors of this number that add to the middle term ie.#" "-19#

#-15, -4#

3) now split the middle term with these factors and then factorise by grouping

.#10t^2 color(blue)(-19t)+6#

#10t^2color(blue)(-15t-4t)+6#

#(10t^2-15t)-(4t-6)#

#5t(2t-3)-2(2t-3)#

#(5t-2)(2t-3)#