How do you factor #121xy + 11zx#? Algebra Polynomials and Factoring Monomial Factors of Polynomials 1 Answer Ratnaker Mehta Jul 26, 2016 #11x(11y+z)#. Explanation: Let us note that, #121=11^2, #:.# The Exp. #= 11*11xy+11zx=11y*11x+z*11x=(11y+z)(11x)=11x(11y+z)#. Answer link Related questions What are Monomial Factors of Polynomials? How do you factor polynomials by finding the greatest common factor? How can a factoring problem be checked? How do you find the greatest common factors of variable expressions? How do you factor #3a+9b+6#? What is the greatest common factor of #a^3-3a^2+4a#? How do you factor #12xy+24xy^2+36xy^3#? How do you find the greatest common factor of #45y^{12}+30y^{10}#? How do you factor #92x^10y^4 - 54x^12y^9#? How do you factor #4x^2+x#? See all questions in Monomial Factors of Polynomials Impact of this question 1720 views around the world You can reuse this answer Creative Commons License