# How do you factor 12y^3+28y-3y-7?

$\left(12 {y}^{3} + 28 y\right) - \left(3 y + 7\right)$
$= 4 y \left(3 y + 7\right) - 1 \left(3 y + 7\right)$
$3 y + 7$ is a common factor to both the terms
 = color(green)((3y+7)(4y - 1)