How do you factor #15c ^ { 2} - 19c - 10# by grouping?

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Answer 1 · 2016-12-29T05:12:26

#c=-2/5# or #c=1 2/3#

#15c²-19c-10=0#

Factorise:

#15c²-25c+6c-10=0#

#5c(3c-5)+2(3c-5)=0#

#(5c+2)(3c-5)=0#

#5c+2=0# or #3c-5=0#

#c=-2/5# or #c=5/3=1 2/3#