How do you factor # 16 - 9y^2#?

1 Answer
Mar 26, 2016

Answer:

#16-9y^2=color(green)((4-3y)(4+3y))#

Explanation:

Remember in general that
#color(white)("XXX")(a^2-b^2)=(a-b)(a+b)#

#16-9y# can be written as
#color(white)("XXX")(4)^2-(3y)^2#

Using #4=a# and #(3y)=b# in the general equation
we see that the original expression can be factored as
#color(white)("XXX")(4-3y)(4+3y)#