How do you factor #18x^2=8#?

2 Answers
Apr 24, 2018

Answer:

x= #+-2/3#

Explanation:

#(18x^2)/18=8/18#
#x^2=8/18=4/9#
#x=+-sqrt(4/9)#
x= #+-2/3#

Apr 24, 2018

Answer:

#2(3x-2)(3x+2)=0#

Explanation:

#"rearrange into "color(blue)"standard form"#

#rArr18x^2-8=0larrcolor(blue)"in standard form"#

#"take out a "color(blue)"common factor "2#

#rArr2(9x^2-4)=0#

#9x^2-4" is a "color(blue)"difference of squares"#

#•color(white)(x)a^2-b^2=(a-b)(a+b)#

#9x^2=(3x)^2rArra=3x" and "4=(2)^2rArrb=2#

#rArr9x^2-4=(3x-2)(3x+2)#

#rArr2(3x-2)(3x+2)=0larrcolor(red)"in factored form"#