How do you factor #24y^2 + 41y + 12#?
Factor f(y) = 24y^2 + 41y + 12
Ans: (8x + 3)(3x + 4)
I use the new AC Method (Google, Yahoo Search)
p' and q' have same sign (Rule of signs)
Factor pairs of 288 --> ...(6, 48)(8, 36)(9, 32). This sum is 41 = -b.
Then p' = 9 and q' = 32
NOTE. Solving by the new AC Method is fast, systematic, no guessing, no lengthy solving by grouping.