How do you factor #25c ^ { 2} - 40cd - 64d ^ { 2}#?

1 Answer
Jun 6, 2018

You can't

Explanation:

Just by eyeballing the expression, and maybe with a little experience, you may notice that the expression looks like the square of a binomial:

#(a\pmb)^2 = a^2\pm2ab+b^2#

In fact, there are three terms, and the first and the last are perfect squares.

Since #25c^2 = (5c)^2 = a^2# and #64d^2 = (8d)^2 = b^2#, this expression is the square of a binomial if and only if the remaning term #-40cd# is, sign apart, twice the multiplication of the other two terms #2ab#.

Unfortunately, you can see that #ab# is already #40cd#. This means that this expression can be written as

#a^2+ab+b^2#

This expression cannot be factorized, i.e. cannot be write as a multiplication of two (or more) polynomial of smaller degree.

Note that writing something like

#a^2+ab+b^2 = a(a+b)+b^2# is not a factorization, since you're not writing your expression as a multiplication of other factors.