# How do you factor #25x^2n - 49 #?

##### 1 Answer

Dec 27, 2015

If

#25x^2n-49 = (5xsqrt(n)-7)(5xsqrt(n)+7)#

#### Explanation:

This question seems a little curious. Should the

In any case, we can use the difference of squares identity:

#a^2-b^2 = (a-b)(a+b)#

with

#25x^2n-49#

#=(5xsqrt(n))^2 - 7^2#

#=(5xsqrt(n)-7)(5xsqrt(n)+7)#