How do you factor #27 - x^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Meave60 Dec 29, 2015 #27-x^3=3^3-x^3=(3-x)(9+3x+x^2)# Explanation: #27-x^3# is an example of the difference of cubes, where #a^3-b^3=(a-b)(a^2+ab+b^2)#. Rewrite #27-x^3# as #3^3-x^3#, where #a=3# and #b=x#. #(3-x)(3^2+(3·x)+x^2)# #=(3-x)(9+3x+x^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 13386 views around the world You can reuse this answer Creative Commons License