How do you factor 27n^2 + 33np + 20p^2?

1 Answer
Mar 22, 2018

can't be factored.

Explanation:

Consider n as variant and p as a constant. Then, factor the trinomial.
#D = d^2 = b^2 - 4ac = (33p)^2 - 4(27)(20p^2) = 1089p^2 - 2160p^2 = - 1079p^2.#
Because D is negative, and isn't a perfect square, therefor, the trinomial can't be factored.