# How do you factor # 27y^3+64#?

##### 1 Answer

May 2, 2016

#### Answer:

#### Explanation:

Note that both

So it is natural to use the sum of cubes identity:

#a^3+b^3=(a+b)(a^2-ab+b^2)#

with

#27y^3+64#

#=(3y)^3+4^3#

#=(3y+4)((3y)^2-(3y)(4)+4^2)#

#=(3y+4)(9y^2-12y+16)#