How do you factor #2a^2-9a+9# by grouping?

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Answer 1 · 2018-03-02T11:34:17

#(a - 3) (2a - 3)#

#2a^2 - 9a + 9#

Note that;

#-9a = -6a -3a#

#-6 xx -3 = -18#

#2a^2 - 6a - 3a + 9#

#(2a^2 - 6a) (-3a + 9)#

#2a(a - 3) -3(a - 3)#

#(a - 3) (2a - 3)#