How do you factor #2k³+3k²+6k+9#?
1 Answer
May 28, 2018
Explanation:
#color(blue)"factor by grouping"#
#=color(red)(k^2)(2k+3)color(red)(+3)(2k+3)#
#"take out the "color(blue)"common factor "(2k+3)#
#=(2k+3)(color(red)(k^2+3))#
#2k^3+3k^2+6k+9=(2k+3)(k^2+3)#
