How do you factor #2m^3-2m^2+3-3m#?

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Answer 1 · 2015-04-29T23:46:41

Collect #2m^2# between the first and second term and #-3# between the third and fourth:
#2m^2(m-1)-3(m-1)# and collect #(m-1)#:
#(m-1)(2m^2-3)#