How do you factor #2s^{2} - 9s + 9#?

1 Answer
anor277
Oct 9, 2016

#(2s-3)(s-3)#

Explanation:

#(2s-3)(s-3)# #=# #2s^2-6s-3s+9# #=# #2s^2-9s+9# as required.

So how did we factorize this quadratic? There was a #"minus"# term in #s# and #9# is clearly #-3^2# or #3^2#, so we had to have #(?-3)(?-3)#, #2s^2# is clearly #2sxxs#, and we observed that the cross products, #2sxx(-3)-3xxs# #=# #-9s#.

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