How do you factor #2x^2 + 23x - 12#?

1 Answer
Jun 28, 2015

Factor: f(x) = 2x^2 + 23x - 12

Explanation:

f(x) = a(x - p)(x - q)

I use the new AC Method (Google, Yahoo Search)
Converted f'(x) = x^2 + 23x - 24. Factor pair of (-24) -> (-1, 24). OK

p' = -1 and q' = 24
.
#p = (p')/a = - 1/2# and #q = (q')/a = 24/2 = 12#

Factored form: #f(x) = 2(x - 1/2)(x + 12)# = (2x - 1)(x + 12)