# How do you factor 2x^2+ 3x - 14?

Jun 28, 2015

Factor $y = 2 {x}^{2} + 3 x - 14$

#### Explanation:

f(x) = 2(x - p)(x = q)
I use the new AC Method (Google, Yahoo Search)
Converted $f ' \left(x\right) = {x}^{2} + 3 x - 28 = \left(x - p '\right) \left(x - q '\right) .$
Factor pairs of (-24) -> (-2, 12)(-4, 7). This sum is 3 = b
p' = -4 and q' = 7
$p = \frac{p '}{a} = - \frac{4}{2} = - 2$ and $q = \frac{q '}{a} = \frac{7}{2}$

Factored form: f(x) = 2(x - 2)(x + 7/2) = (x - 2)(2x + 7)