How do you factor #2x^2 - 4x -70#?

2 Answers
Chanelle K.
Apr 13, 2018

the answer is #2(x-7)(x+5)#

Explanation:

first you have to take out(aka find what they have in common) which would be #2# so you'll have #2(x^2-2x-35)# and now you have to worry about the parenthesis and factor so you'll now have #(x-7)(x+5)# but you still have the #2# so you have to put that at the front first.

Binayaka C.
Apr 13, 2018

#2(x- 7)( x +5)#

Explanation:

#2 x^2-4 x-70 = 2 x^2-14 x +10 x-70#

#= 2 x(x- 7) +10(x-7)#

#=(x- 7)( 2 x +10)#

#=2(x- 7)( x +5)# [Ans]

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