# How do you factor 2x^2 + 4x - 96?

$2 {x}^{2} + 4 x - 96$
$= 2 \left({x}^{2} + 2 x - 48\right)$
Noting that $48$ has the obvious factor pair $\left(6 , 8\right)$ whose difference is $2$ (the coefficient of $x$)
$= 2 \left(x + 8\right) \left(x - 6\right)$