# How do you factor: 2x^3 + 7x^2 - 3x -18?

Apr 5, 2018

${x}^{2} \left(2 x + 7\right) - 3 \left(x + 6\right)$

Here's how I did it:

#### Explanation:

$2 {x}^{3} + 7 {x}^{2} - 3 x - 18$

We will factor this by grouping:
$\left(2 {x}^{3} + 7 {x}^{2}\right) + \left(- 3 x - 18\right)$

To factor, we have to see what everything has in common. For $2 {x}^{3} + 7 {x}^{2}$, both expressions have ${x}^{2}$ in them, so we can take ${x}^{2}$ out:
${x}^{2} \left(2 x + 7\right)$

For $- \left(3 x + 18\right)$, they both have $- 3$ in common, so we take that out:
$- 3 \left(x + 6\right)$

Now we combine these two expressions:
${x}^{2} \left(2 x + 7\right) - 3 \left(x + 6\right)$