How do you factor #36x^2 - 169y^2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Don't Memorise May 22, 2015 We know that #color(blue)(a^2 - b^2 = (a+b)(a-b)# # 36 x^2 - 169y^2 = (6x)^2 - (13y)^2# # (6x)^2 - (13y)^2 = (6x-13y)(6x+13y)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1838 views around the world You can reuse this answer Creative Commons License