How do you factor #3m^2-10m+8=0#?

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Answer 1 · 2015-07-13T17:49:24

#color(green)((3m-4)(m-2) =0#

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like #am^2 + bm + c#, we need to think of 2 numbers such that:

#N_1*N_2 = a*c = 3*8= 24#
and,
#N_1 +N_2 = b = -10#

After trying out a few numbers we get #N_1 = -6# and #N_2 =-4#
#-6*-4 = 24# and #-6+(-4)= -10#

#3m^2-10m+8=0#

#3m^2-6m-4m+8=0#

#3m(m-2) -4(m-2)=0#
#color(green)((3m-4)(m-2) =0#