# How do you factor 3m^2-10m+8=0?

Jul 13, 2015

color(green)((3m-4)(m-2) =0

#### Explanation:

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like $a {m}^{2} + b m + c$, we need to think of 2 numbers such that:

${N}_{1} \cdot {N}_{2} = a \cdot c = 3 \cdot 8 = 24$
and,
${N}_{1} + {N}_{2} = b = - 10$

After trying out a few numbers we get ${N}_{1} = - 6$ and ${N}_{2} = - 4$
$- 6 \cdot - 4 = 24$ and $- 6 + \left(- 4\right) = - 10$

$3 {m}^{2} - 10 m + 8 = 0$

$3 {m}^{2} - 6 m - 4 m + 8 = 0$

$3 m \left(m - 2\right) - 4 \left(m - 2\right) = 0$
color(green)((3m-4)(m-2) =0