How do you factor #3n^2-8n+5#?

2 Answers

Answer:

#(n-1)(3n-5)#

Explanation:

1.) write #-8n# as a sum or difference
#=>3n^2-3n-5n +5#

2.) factor out #3n# and #-5# from the expression:
#=>3n (n-1)-5(n-1)#

3.) factor out #(n-1)# from the expression
#=>(n-1)(3n-5)#

Mar 31, 2018

Answer:

#(3n - 5)(n - 1)#

Explanation:

#3n^2# only has two factors, #3n and n#

5 only has two factors , 5 and 1. These are both negative to multiply to +5 and add to make -8