# How do you factor 3n^3-4n^2-6n+8?

$f \left(x\right) = 3 n \left({n}^{2} - 2\right) - 4 \left({n}^{2} - 2\right) = \left({n}^{2} - 2\right) \left(3 n - 4\right)$