How do you factor #3n^3-4n^2-6n+8#? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer Nghi N. May 16, 2015 Group first term and third term: #f(x) = 3n(n^2 - 2) - 4(n^2 - 2) = (n^2 - 2)(3n - 4)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 1553 views around the world You can reuse this answer Creative Commons License