How do you factor #3w^2 - 10w-8#?

2 Answers
Pallu
Sep 25, 2017

The factors are # (3w +2) and (w-4)#

Explanation:

#3w^2 - 10w-8#

we split the middle term such that , the sum of the numbers will give middle term # -10#and product will give #3\times -8 = -24# i.e. product of coefficient of #x^2# and last term.

#3w^2-12 w + 2w-8#

#3w(w-4) + 2(w-4)#

# (3w +2) (w-4)#

The factors are # (3w +2) and (w-4)#

Gaya3
Sep 25, 2017

#(w-4) (3w+2)#

Explanation:

#3w^2 - 10w -8#
#=3w^2 - 12w + 2w -8# ...... as 12 & 2 are factors of #3*8# (product first and last coefficients)

#=color(red)(3w)color(blue)((w-4)) +color(red)(2) color(blue)((w-4))#

#=color(blue)((w-4)) color(red)((3w+2))#

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