How do you factor #3x^2-2#?

1 Answer
RedRobin9688
Jun 26, 2018

#3(x-sqrt(2/3))(x+sqrt(2/3))#

Explanation:

First divide by the number in front of #x^2#

#(3x^2-2)/(color(red)3) rarr x^2-2/3#

Solve for roots by setting equal to 0

#x^2-2/3=0 rarr x^2=2/3 rarr x=+-sqrt(2/3)#

Multiply by 3 and #(x-"root")# such as

#3(x-sqrt(2/3))(x--sqrt(2/3)) rarr 3(x-sqrt(2/3))(x+sqrt(2/3))#

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