How do you factor #3x ^ { 2} + 3x - 2x - 2#?

1 Answer
Jun 29, 2017

#3x^2+3x-2x-2 = (3x-2)(x+1)#

Explanation:

Given:

#3x^2+3x-2x-2#

Note that the ratio between the first and second terms is the same as that between the third and fourth terms. So this quadrinomial will factor by grouping:

#3x^2+3x-2x-2 = (3x^2+3x)-(2x+2)#

#color(white)(3x^2+3x-2x-2) = 3x(x+1)-2(x+1)#

#color(white)(3x^2+3x-2x-2) = (3x-2)(x+1)#